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(((2*a^2)/3)*b^5)^4 = 0
16/81*a^8*b^20 = 0
x należy do R
x in (-oo:+oo)
| 3(3u+2v)-a(3u+2v)= | | x(2x-9)=5 | | 2x-135=-87 | | 36x^7+36x^4=0 | | 4(x+3)*2=(25x-2)*2 | | 4(x+3)2=(25x-2)2 | | f(3d)=3f(d) | | 13+-1=12 | | 2x+12=124 | | 8w+4y=26 | | 2(x+3)=5(x-23) | | -5=-8(3z-10) | | 0-2/3 | | -2-3(2p+2)=12-2p | | 3/5=3/8×-3/2 | | 25x+10y=40 | | 15-5(5-3x)=2(5-x)-8x | | 3(5q-7)=42 | | ln(y)=5t+2 | | 5x^3-21x^2+12x-4=0 | | 5x/(x-5) | | (16x-24)(4/5)=35 | | 186000/(x/60) | | 6(4-y)=-36 | | 186000/ | | -36-24= | | 13x+9-15x=29 | | 2x^3-8x^2-24x=2x(ax+b)(cx+d) | | 10x+12x=264 | | 11d+9d-2=5d+29 | | 2x^3-6x^2-4x+12=0 | | 5x^2=6+8x |